Base | Representation |
---|---|
bin | 110100001101001100… |
… | …1011001000001011111 |
3 | 101201101021112101002212 |
4 | 1220122121121001133 |
5 | 3314101133412112 |
6 | 123300433311035 |
7 | 11046145250642 |
oct | 1503231310137 |
9 | 351337471085 |
10 | 112112013407 |
11 | 43601344039 |
12 | 1988a10547b |
13 | a758c32b94 |
14 | 55d78b9a59 |
15 | 2db2734522 |
hex | 1a1a65905f |
112112013407 has 2 divisors, whose sum is σ = 112112013408. Its totient is φ = 112112013406.
The previous prime is 112112013401. The next prime is 112112013421. The reversal of 112112013407 is 704310211211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112112013407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112112013401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056006703 + 56056006704.
It is an arithmetic number, because the mean of its divisors is an integer number (56056006704).
Almost surely, 2112112013407 is an apocalyptic number.
112112013407 is a deficient number, since it is larger than the sum of its proper divisors (1).
112112013407 is an equidigital number, since it uses as much as digits as its factorization.
112112013407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 112112013407 its reverse (704310211211), we get a palindrome (816422224618).
The spelling of 112112013407 in words is "one hundred twelve billion, one hundred twelve million, thirteen thousand, four hundred seven".
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