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112112111209993 is a prime number
BaseRepresentation
bin11001011111011100100010…
…100100000100111000001001
3112200221210221210102012002221
4121133130202210010320021
5104143321100432204433
61034235332021054041
732420555425551346
oct3137344244047011
9480853853365087
10112112111209993
11327a4530026434
12106a80b3257321
134a73185546abb
141d9838013b7cd
15ce645ed1672d
hex65f722904e09

112112111209993 has 2 divisors, whose sum is σ = 112112111209994. Its totient is φ = 112112111209992.

The previous prime is 112112111209991. The next prime is 112112111210119. The reversal of 112112111209993 is 399902111211211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105984718932544 + 6127392277449 = 10294888^2 + 2475357^2 .

It is a cyclic number.

It is not a de Polignac number, because 112112111209993 - 21 = 112112111209991 is a prime.

Together with 112112111209991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (112112111209991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056055604996 + 56056055604997.

It is an arithmetic number, because the mean of its divisors is an integer number (56056055604997).

Almost surely, 2112112111209993 is an apocalyptic number.

It is an amenable number.

112112111209993 is a deficient number, since it is larger than the sum of its proper divisors (1).

112112111209993 is an equidigital number, since it uses as much as digits as its factorization.

112112111209993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 43.

The spelling of 112112111209993 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred eleven million, two hundred nine thousand, nine hundred ninety-three".