Base | Representation |
---|---|
bin | 10000010100001000001… |
… | …001010001100000101001 |
3 | 10222011210222221002101022 |
4 | 100110020021101200221 |
5 | 121332030004104001 |
6 | 2215011543102225 |
7 | 143666322140243 |
oct | 20241011214051 |
9 | 3864728832338 |
10 | 1121123113001 |
11 | 3a2513851481 |
12 | 161345a41975 |
13 | 8194c066bc8 |
14 | 3c3969c7093 |
15 | 1e26a11b11b |
hex | 10508251829 |
1121123113001 has 2 divisors, whose sum is σ = 1121123113002. Its totient is φ = 1121123113000.
The previous prime is 1121123112983. The next prime is 1121123113003. The reversal of 1121123113001 is 1003113211211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1103972591401 + 17150521600 = 1050701^2 + 130960^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121123113001 is a prime.
Together with 1121123113003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1121123113003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560561556500 + 560561556501.
It is an arithmetic number, because the mean of its divisors is an integer number (560561556501).
Almost surely, 21121123113001 is an apocalyptic number.
It is an amenable number.
1121123113001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121123113001 is an equidigital number, since it uses as much as digits as its factorization.
1121123113001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1121123113001 its reverse (1003113211211), we get a palindrome (2124236324212).
The spelling of 1121123113001 in words is "one trillion, one hundred twenty-one billion, one hundred twenty-three million, one hundred thirteen thousand, one".
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