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1121130000157 is a prime number
BaseRepresentation
bin10000010100001000100…
…011100010111100011101
310222011211110212222210011
4100110020203202330131
5121332033240001112
62215012350443221
7143666434523356
oct20241043427435
93864743788704
101121130000157
113a2517725942
12161348203511
138195060894b
143c39789ad2d
151e26aa2baa7
hex105088e2f1d

1121130000157 has 2 divisors, whose sum is σ = 1121130000158. Its totient is φ = 1121130000156.

The previous prime is 1121130000121. The next prime is 1121130000161. The reversal of 1121130000157 is 7510000311211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 708793926201 + 412336073956 = 841899^2 + 642134^2 .

It is an emirp because it is prime and its reverse (7510000311211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121130000157 - 239 = 571374186269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121134000157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560565000078 + 560565000079.

It is an arithmetic number, because the mean of its divisors is an integer number (560565000079).

Almost surely, 21121130000157 is an apocalyptic number.

It is an amenable number.

1121130000157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121130000157 is an equidigital number, since it uses as much as digits as its factorization.

1121130000157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 210, while the sum is 22.

Adding to 1121130000157 its reverse (7510000311211), we get a palindrome (8631130311368).

The spelling of 1121130000157 in words is "one trillion, one hundred twenty-one billion, one hundred thirty million, one hundred fifty-seven", and thus it is an aban number.