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112113013147 is a prime number
BaseRepresentation
bin110100001101001110…
…1001101000110011011
3101201101100102011111021
41220122131031012123
53314101412410042
6123300510543311
711046156613432
oct1503235150633
9351340364437
10112113013147
1143601967173
121988a507b37
13a7591c2c45
1455d7a9a119
152db2880867
hex1a1a74d19b

112113013147 has 2 divisors, whose sum is σ = 112113013148. Its totient is φ = 112113013146.

The previous prime is 112113013093. The next prime is 112113013171. The reversal of 112113013147 is 741310311211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112113013147 is a prime.

It is not a weakly prime, because it can be changed into another prime (112113013847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056506573 + 56056506574.

It is an arithmetic number, because the mean of its divisors is an integer number (56056506574).

Almost surely, 2112113013147 is an apocalyptic number.

112113013147 is a deficient number, since it is larger than the sum of its proper divisors (1).

112113013147 is an equidigital number, since it uses as much as digits as its factorization.

112113013147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 112113013147 its reverse (741310311211), we get a palindrome (853423324358).

The spelling of 112113013147 in words is "one hundred twelve billion, one hundred thirteen million, thirteen thousand, one hundred forty-seven".