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1121130211130 = 25532115340021
BaseRepresentation
bin10000010100001000100…
…100010110011100111010
310222011211111021201011222
4100110020210112130322
5121332033313224010
62215012355152042
7143666436362426
oct20241044263472
93864744251158
101121130211130
113a251785a3a6
121613482a5622
1381950680997
143c397913b86
151e26aa6e355
hex1050891673a

1121130211130 has 16 divisors (see below), whose sum is σ = 2056110501384. Its totient is φ = 439990724160.

The previous prime is 1121130211127. The next prime is 1121130211181. The reversal of 1121130211130 is 311120311211.

It can be written as a sum of positive squares in 4 ways, for example, as 1003705426201 + 117424784929 = 1001851^2 + 342673^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1121130211099 and 1121130211108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1057669481 + ... + 1057670540.

Almost surely, 21121130211130 is an apocalyptic number.

1121130211130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1121130211130 is a deficient number, since it is larger than the sum of its proper divisors (934980290254).

1121130211130 is a wasteful number, since it uses less digits than its factorization.

1121130211130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2115340081.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1121130211130 its reverse (311120311211), we get a palindrome (1432250522341).

The spelling of 1121130211130 in words is "one trillion, one hundred twenty-one billion, one hundred thirty million, two hundred eleven thousand, one hundred thirty".

Divisors: 1 2 5 10 53 106 265 530 2115340021 4230680042 10576700105 21153400210 112113021113 224226042226 560565105565 1121130211130