Base | Representation |
---|---|
bin | 11001011111011101101001… |
… | …100010101000010101100111 |
3 | 112200221221000210010021010122 |
4 | 121133131221202220111213 |
5 | 104143331020303411122 |
6 | 1034240050120112155 |
7 | 32420630065324151 |
oct | 3137355142502547 |
9 | 480857023107118 |
10 | 112113302013287 |
11 | 327a4a91220593 |
12 | 106a838600565b |
13 | 4a7331516b233 |
14 | 1d98454355ad1 |
15 | ce64ce637142 |
hex | 65f7698a8567 |
112113302013287 has 2 divisors, whose sum is σ = 112113302013288. Its totient is φ = 112113302013286.
The previous prime is 112113302013253. The next prime is 112113302013329. The reversal of 112113302013287 is 782310203311211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112113302013287 - 220 = 112113300964711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112113302013247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056651006643 + 56056651006644.
It is an arithmetic number, because the mean of its divisors is an integer number (56056651006644).
Almost surely, 2112113302013287 is an apocalyptic number.
112113302013287 is a deficient number, since it is larger than the sum of its proper divisors (1).
112113302013287 is an equidigital number, since it uses as much as digits as its factorization.
112113302013287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 35.
Adding to 112113302013287 its reverse (782310203311211), we get a palindrome (894423505324498).
The spelling of 112113302013287 in words is "one hundred twelve trillion, one hundred thirteen billion, three hundred two million, thirteen thousand, two hundred eighty-seven".
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