Base | Representation |
---|---|
bin | 110100001101010000… |
… | …0111111101010111101 |
3 | 101201101102021122102011 |
4 | 1220122200333222331 |
5 | 3314102141203332 |
6 | 123300544131221 |
7 | 11046201222226 |
oct | 1503240775275 |
9 | 351342248364 |
10 | 112114006717 |
11 | 436024856a9 |
12 | 1988a906b11 |
13 | a75948025b |
14 | 55d7c7824d |
15 | 2db29c9e47 |
hex | 1a1a83fabd |
112114006717 has 2 divisors, whose sum is σ = 112114006718. Its totient is φ = 112114006716.
The previous prime is 112114006709. The next prime is 112114006747. The reversal of 112114006717 is 717600411211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 87229259716 + 24884747001 = 295346^2 + 157749^2 .
It is a cyclic number.
It is not a de Polignac number, because 112114006717 - 23 = 112114006709 is a prime.
It is a super-2 number, since 2×1121140067172 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112114006747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56057003358 + 56057003359.
It is an arithmetic number, because the mean of its divisors is an integer number (56057003359).
Almost surely, 2112114006717 is an apocalyptic number.
It is an amenable number.
112114006717 is a deficient number, since it is larger than the sum of its proper divisors (1).
112114006717 is an equidigital number, since it uses as much as digits as its factorization.
112114006717 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2352, while the sum is 31.
Adding to 112114006717 its reverse (717600411211), we get a palindrome (829714417928).
The spelling of 112114006717 in words is "one hundred twelve billion, one hundred fourteen million, six thousand, seven hundred seventeen".
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