Base | Representation |
---|---|
bin | 1010001100100111111101… |
… | …0101100100101100110101 |
3 | 1110200212010121221112212002 |
4 | 2203021333111210230311 |
5 | 2432144134224114331 |
6 | 35502415552505045 |
7 | 2235016560036224 |
oct | 243117725445465 |
9 | 43625117845762 |
10 | 11212001004341 |
11 | 3632a8a2a8315 |
12 | 1310b6454b185 |
13 | 634396b69c17 |
14 | 2aa941456cbb |
15 | 1469b34eb9cb |
hex | a327f564b35 |
11212001004341 has 2 divisors, whose sum is σ = 11212001004342. Its totient is φ = 11212001004340.
The previous prime is 11212001004311. The next prime is 11212001004377. The reversal of 11212001004341 is 14340010021211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9214078120900 + 1997922883441 = 3035470^2 + 1413479^2 .
It is a cyclic number.
It is not a de Polignac number, because 11212001004341 - 26 = 11212001004277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212001004311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606000502170 + 5606000502171.
It is an arithmetic number, because the mean of its divisors is an integer number (5606000502171).
Almost surely, 211212001004341 is an apocalyptic number.
It is an amenable number.
11212001004341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212001004341 is an equidigital number, since it uses as much as digits as its factorization.
11212001004341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 11212001004341 its reverse (14340010021211), we get a palindrome (25552011025552).
The spelling of 11212001004341 in words is "eleven trillion, two hundred twelve billion, one million, four thousand, three hundred forty-one".
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