Base | Representation |
---|---|
bin | 1010001100100111111111… |
… | …1111111100000100000011 |
3 | 1110200212011101211210001212 |
4 | 2203021333333330010003 |
5 | 2432144200100010313 |
6 | 35502421030520335 |
7 | 2235020053322411 |
oct | 243117777740403 |
9 | 43625141753055 |
10 | 11212012110083 |
11 | 3632a955a3214 |
12 | 1310b682060ab |
13 | 634399257b75 |
14 | 2aa942b082b1 |
15 | 1469b44923a8 |
hex | a327fffc103 |
11212012110083 has 2 divisors, whose sum is σ = 11212012110084. Its totient is φ = 11212012110082.
The previous prime is 11212012110007. The next prime is 11212012110121. The reversal of 11212012110083 is 38001121021211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212012110083 - 210 = 11212012109059 is a prime.
It is a super-2 number, since 2×112120121100832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11212012116083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606006055041 + 5606006055042.
It is an arithmetic number, because the mean of its divisors is an integer number (5606006055042).
Almost surely, 211212012110083 is an apocalyptic number.
11212012110083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212012110083 is an equidigital number, since it uses as much as digits as its factorization.
11212012110083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 23.
Adding to 11212012110083 its reverse (38001121021211), we get a palindrome (49213133131294).
The spelling of 11212012110083 in words is "eleven trillion, two hundred twelve billion, twelve million, one hundred ten thousand, eighty-three".
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