Base | Representation |
---|---|
bin | 11001011111100100001011… |
… | …010000110010001101111011 |
3 | 112200222121010012021121200121 |
4 | 121133210023100302031323 |
5 | 104143434343403231301 |
6 | 1034243205350114111 |
7 | 32421265544116603 |
oct | 3137441320621573 |
9 | 480877105247617 |
10 | 112120310211451 |
11 | 327a7a581645a3 |
12 | 106a980104b937 |
13 | 4a73b91084859 |
14 | 1d9891b007c03 |
15 | ce678ea203a1 |
hex | 65f90b43237b |
112120310211451 has 2 divisors, whose sum is σ = 112120310211452. Its totient is φ = 112120310211450.
The previous prime is 112120310211379. The next prime is 112120310211461. The reversal of 112120310211451 is 154112013021211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112120310211451 - 213 = 112120310203259 is a prime.
It is not a weakly prime, because it can be changed into another prime (112120310211461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060155105725 + 56060155105726.
It is an arithmetic number, because the mean of its divisors is an integer number (56060155105726).
Almost surely, 2112120310211451 is an apocalyptic number.
112120310211451 is a deficient number, since it is larger than the sum of its proper divisors (1).
112120310211451 is an equidigital number, since it uses as much as digits as its factorization.
112120310211451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 25.
Adding to 112120310211451 its reverse (154112013021211), we get a palindrome (266232323232662).
The spelling of 112120310211451 in words is "one hundred twelve trillion, one hundred twenty billion, three hundred ten million, two hundred eleven thousand, four hundred fifty-one".
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