Base | Representation |
---|---|
bin | 1010001100101000000110… |
… | …1100011010011011100111 |
3 | 1110200212020101100110211211 |
4 | 2203022001230122123213 |
5 | 2432144224334433043 |
6 | 35502423524212251 |
7 | 2235020550115132 |
oct | 243120154323347 |
9 | 43625211313754 |
10 | 11212040546023 |
11 | 3632aaa655599 |
12 | 1310b7583a087 |
13 | 6343a2102c75 |
14 | 2aa9467cb219 |
15 | 1469b6c0ca9d |
hex | a3281b1a6e7 |
11212040546023 has 2 divisors, whose sum is σ = 11212040546024. Its totient is φ = 11212040546022.
The previous prime is 11212040546009. The next prime is 11212040546051. The reversal of 11212040546023 is 32064504021211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11212040546023 is a prime.
It is a super-2 number, since 2×112120405460232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212040546423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606020273011 + 5606020273012.
It is an arithmetic number, because the mean of its divisors is an integer number (5606020273012).
Almost surely, 211212040546023 is an apocalyptic number.
11212040546023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212040546023 is an equidigital number, since it uses as much as digits as its factorization.
11212040546023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 11212040546023 its reverse (32064504021211), we get a palindrome (43276544567234).
The spelling of 11212040546023 in words is "eleven trillion, two hundred twelve billion, forty million, five hundred forty-six thousand, twenty-three".
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