Base | Representation |
---|---|
bin | 10000010100001101010… |
… | …100110011000110011101 |
3 | 10222012001001110102201102 |
4 | 100110031110303012131 |
5 | 121332214231122003 |
6 | 2215024325522445 |
7 | 144001425632201 |
oct | 20241524630635 |
9 | 3865031412642 |
10 | 1121210020253 |
11 | 3a2558910154 |
12 | 16136ab73425 |
13 | 8196407520b |
14 | 3c3a436ab01 |
15 | 1e272a86588 |
hex | 1050d53319d |
1121210020253 has 2 divisors, whose sum is σ = 1121210020254. Its totient is φ = 1121210020252.
The previous prime is 1121210020207. The next prime is 1121210020267. The reversal of 1121210020253 is 3520200121211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1120437069049 + 772951204 = 1058507^2 + 27802^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121210020253 - 210 = 1121210019229 is a prime.
It is a super-2 number, since 2×11212100202532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121210020153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560605010126 + 560605010127.
It is an arithmetic number, because the mean of its divisors is an integer number (560605010127).
Almost surely, 21121210020253 is an apocalyptic number.
It is an amenable number.
1121210020253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121210020253 is an equidigital number, since it uses as much as digits as its factorization.
1121210020253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 1121210020253 its reverse (3520200121211), we get a palindrome (4641410141464).
The spelling of 1121210020253 in words is "one trillion, one hundred twenty-one billion, two hundred ten million, twenty thousand, two hundred fifty-three".
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