Base | Representation |
---|---|
bin | 1010001100101000010101… |
… | …0111100110111110000011 |
3 | 1110200212101200100212212121 |
4 | 2203022011113212332003 |
5 | 2432144341130414334 |
6 | 35502434005505111 |
7 | 2235022226144653 |
oct | 243120527467603 |
9 | 43625350325777 |
10 | 11212102201219 |
11 | 3633031436aa7 |
12 | 1310b92412197 |
13 | 6343b1b0c42a |
14 | 2aa950a7a363 |
15 | 1469bc33adb4 |
hex | a32855e6f83 |
11212102201219 has 2 divisors, whose sum is σ = 11212102201220. Its totient is φ = 11212102201218.
The previous prime is 11212102201199. The next prime is 11212102201241. The reversal of 11212102201219 is 91210220121211.
11212102201219 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11212102201219 - 231 = 11209954717571 is a prime.
It is a super-2 number, since 2×112121022012192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11212102201193 and 11212102201202.
It is not a weakly prime, because it can be changed into another prime (11212102205219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606051100609 + 5606051100610.
It is an arithmetic number, because the mean of its divisors is an integer number (5606051100610).
Almost surely, 211212102201219 is an apocalyptic number.
11212102201219 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212102201219 is an equidigital number, since it uses as much as digits as its factorization.
11212102201219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 25.
The spelling of 11212102201219 in words is "eleven trillion, two hundred twelve billion, one hundred two million, two hundred one thousand, two hundred nineteen".
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