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1121210222113 is a prime number
BaseRepresentation
bin10000010100001101010…
…101100100011000100001
310222012001001211200121201
4100110031111210120201
5121332214304101423
62215024334121201
7144001430432542
oct20241525443041
93865031750551
101121210222113
113a2558a38883
1216136b050201
1381964116067
143c3a43c04c9
151e272ac62ad
hex1050d564621

1121210222113 has 2 divisors, whose sum is σ = 1121210222114. Its totient is φ = 1121210222112.

The previous prime is 1121210222101. The next prime is 1121210222123. The reversal of 1121210222113 is 3112220121211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 815060479249 + 306149742864 = 902807^2 + 553308^2 .

It is an emirp because it is prime and its reverse (3112220121211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121210222113 - 25 = 1121210222081 is a prime.

It is a super-2 number, since 2×11212102221132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1121210222123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560605111056 + 560605111057.

It is an arithmetic number, because the mean of its divisors is an integer number (560605111057).

Almost surely, 21121210222113 is an apocalyptic number.

It is an amenable number.

1121210222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121210222113 is an equidigital number, since it uses as much as digits as its factorization.

1121210222113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1121210222113 its reverse (3112220121211), we get a palindrome (4233430343324).

The spelling of 1121210222113 in words is "one trillion, one hundred twenty-one billion, two hundred ten million, two hundred twenty-two thousand, one hundred thirteen".