Search a number
-
+
1121211202020 = 22357133753104717
BaseRepresentation
bin10000010100001101011…
…001010011100111100100
310222012001010200110210120
4100110031121103213210
5121332220031431040
62215024411121540
7144001441653450
oct20241531234744
93865033613716
101121211202020
113a2559548018
1216136b4432b0
138196439a0a0
143c3a4597660
151e272c1b7d0
hex1050d6539e4

1121211202020 has 384 divisors, whose sum is σ = 4043207218176. Its totient is φ = 225824661504.

The previous prime is 1121211201977. The next prime is 1121211202063. The reversal of 1121211202020 is 202021121211.

It is an interprime number because it is at equal distance from previous prime (1121211201977) and next prime (1121211202063).

It is a super-2 number, since 2×11212112020202 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 10654702 + ... + 10759418.

It is an arithmetic number, because the mean of its divisors is an integer number (10529185464).

Almost surely, 21121211202020 is an apocalyptic number.

1121211202020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1121211202020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2021603609088).

1121211202020 is an abundant number, since it is smaller than the sum of its proper divisors (2921996016156).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1121211202020 is a wasteful number, since it uses less digits than its factorization.

1121211202020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104839 (or 104837 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 1121211202020 its reverse (202021121211), we get a palindrome (1323232323231).

It can be divided in two parts, 1121211 and 202020, that added together give a palindrome (1323231).

The spelling of 1121211202020 in words is "one trillion, one hundred twenty-one billion, two hundred eleven million, two hundred two thousand, twenty".