Base | Representation |
---|---|
bin | 10100111000100101… |
… | …10100011000000101 |
3 | 1001221101120101010202 |
4 | 22130102310120011 |
5 | 140430300112123 |
6 | 5052322300245 |
7 | 544563251204 |
oct | 123422643005 |
9 | 31841511122 |
10 | 11212113413 |
11 | 4833a44836 |
12 | 220aab7685 |
13 | 1098b63447 |
14 | 78512723b |
15 | 4594dca28 |
hex | 29c4b4605 |
11212113413 has 2 divisors, whose sum is σ = 11212113414. Its totient is φ = 11212113412.
The previous prime is 11212113401. The next prime is 11212113463. The reversal of 11212113413 is 31431121211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11212056769 + 56644 = 105887^2 + 238^2 .
It is a cyclic number.
It is not a de Polignac number, because 11212113413 - 224 = 11195336197 is a prime.
It is a super-2 number, since 2×112121134132 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212113463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606056706 + 5606056707.
It is an arithmetic number, because the mean of its divisors is an integer number (5606056707).
Almost surely, 211212113413 is an apocalyptic number.
It is an amenable number.
11212113413 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212113413 is an equidigital number, since it uses as much as digits as its factorization.
11212113413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144, while the sum is 20.
Adding to 11212113413 its reverse (31431121211), we get a palindrome (42643234624).
The spelling of 11212113413 in words is "eleven billion, two hundred twelve million, one hundred thirteen thousand, four hundred thirteen".
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