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112121201000111 is a prime number
BaseRepresentation
bin11001011111100101000000…
…010110110111111010101111
3112200222200102021110101000012
4121133211000112313322233
5104143443204424000421
61034243434010523435
732421326611522232
oct3137450026677257
9480880367411005
10112121201000111
11327a8374a75276
12106a9a0b43657b
134a73ca37a4634
141d989a3447419
15ce67e2d2c95b
hex65f9405b7eaf

112121201000111 has 2 divisors, whose sum is σ = 112121201000112. Its totient is φ = 112121201000110.

The previous prime is 112121201000099. The next prime is 112121201000161. The reversal of 112121201000111 is 111000102121211.

It is a weak prime.

It is an emirp because it is prime and its reverse (111000102121211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112121201000111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112121201000161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060600500055 + 56060600500056.

It is an arithmetic number, because the mean of its divisors is an integer number (56060600500056).

Almost surely, 2112121201000111 is an apocalyptic number.

112121201000111 is a deficient number, since it is larger than the sum of its proper divisors (1).

112121201000111 is an equidigital number, since it uses as much as digits as its factorization.

112121201000111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 112121201000111 its reverse (111000102121211), we get a palindrome (223121303121322).

The spelling of 112121201000111 in words is "one hundred twelve trillion, one hundred twenty-one billion, two hundred one million, one hundred eleven", and thus it is an aban number.