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11212120195817 is a prime number
BaseRepresentation
bin1010001100101000011001…
…1100010000001011101001
31110200212102221020002211012
42203022012130100023221
52432144410232231232
635502435451313305
72235022535122232
oct243120634201351
943625387202735
1011212120195817
113633040607672
121310b9844b835
136343b576cb18
142aa953202089
151469bdbe29b2
hexa32867102e9

11212120195817 has 2 divisors, whose sum is σ = 11212120195818. Its totient is φ = 11212120195816.

The previous prime is 11212120195811. The next prime is 11212120195823. The reversal of 11212120195817 is 71859102121211.

It is a balanced prime because it is at equal distance from previous prime (11212120195811) and next prime (11212120195823).

It can be written as a sum of positive squares in only one way, i.e., 10213271864041 + 998848331776 = 3195821^2 + 999424^2 .

It is a cyclic number.

It is not a de Polignac number, because 11212120195817 - 220 = 11212119147241 is a prime.

It is not a weakly prime, because it can be changed into another prime (11212120195811) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606060097908 + 5606060097909.

It is an arithmetic number, because the mean of its divisors is an integer number (5606060097909).

Almost surely, 211212120195817 is an apocalyptic number.

It is an amenable number.

11212120195817 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212120195817 is an equidigital number, since it uses as much as digits as its factorization.

11212120195817 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 41.

The spelling of 11212120195817 in words is "eleven trillion, two hundred twelve billion, one hundred twenty million, one hundred ninety-five thousand, eight hundred seventeen".