Base | Representation |
---|---|
bin | 1010001100101000011001… |
… | …1111001100100010101011 |
3 | 1110200212102222200022011002 |
4 | 2203022012133030202223 |
5 | 2432144410431423324 |
6 | 35502435520025215 |
7 | 2235022544514455 |
oct | 243120637144253 |
9 | 43625388608132 |
10 | 11212120967339 |
11 | 3633040a94296 |
12 | 1310b9876220b |
13 | 6343b5980046 |
14 | 2aa9533632d5 |
15 | 1469bdce63ae |
hex | a32867cc8ab |
11212120967339 has 2 divisors, whose sum is σ = 11212120967340. Its totient is φ = 11212120967338.
The previous prime is 11212120967309. The next prime is 11212120967353. The reversal of 11212120967339 is 93376902121211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212120967339 - 28 = 11212120967083 is a prime.
It is a super-3 number, since 3×112121209673393 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11212120967293 and 11212120967302.
It is not a weakly prime, because it can be changed into another prime (11212120967309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606060483669 + 5606060483670.
It is an arithmetic number, because the mean of its divisors is an integer number (5606060483670).
Almost surely, 211212120967339 is an apocalyptic number.
11212120967339 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212120967339 is an equidigital number, since it uses as much as digits as its factorization.
11212120967339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 244944, while the sum is 47.
The spelling of 11212120967339 in words is "eleven trillion, two hundred twelve billion, one hundred twenty million, nine hundred sixty-seven thousand, three hundred thirty-nine".
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