Base | Representation |
---|---|
bin | 1010001100101000011001… |
… | …1111010100100010100111 |
3 | 1110200212102222201222002120 |
4 | 2203022012133110202213 |
5 | 2432144410434000403 |
6 | 35502435520441023 |
7 | 2235022545012132 |
oct | 243120637244247 |
9 | 43625388658076 |
10 | 11212121000103 |
11 | 3633041006971 |
12 | 1310b98779173 |
13 | 6343b5991c2a |
14 | 2aa953371219 |
15 | 1469bdd00e53 |
hex | a32867d48a7 |
11212121000103 has 8 divisors (see below), whose sum is σ = 14949510515328. Its totient is φ = 7474739409144.
The previous prime is 11212121000071. The next prime is 11212121000107. The reversal of 11212121000103 is 30100012121211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11212121000103 - 25 = 11212121000071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11212121000107) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3438150 + ... + 5851932.
It is an arithmetic number, because the mean of its divisors is an integer number (1868688814416).
Almost surely, 211212121000103 is an apocalyptic number.
11212121000103 is a deficient number, since it is larger than the sum of its proper divisors (3737389515225).
11212121000103 is a wasteful number, since it uses less digits than its factorization.
11212121000103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3962133.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 11212121000103 its reverse (30100012121211), we get a palindrome (41312133121314).
The spelling of 11212121000103 in words is "eleven trillion, two hundred twelve billion, one hundred twenty-one million, one hundred three", and thus it is an aban number.
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