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11212121000107 is a prime number
BaseRepresentation
bin1010001100101000011001…
…1111010100100010101011
31110200212102222201222002201
42203022012133110202223
52432144410434000412
635502435520441031
72235022545012136
oct243120637244253
943625388658081
1011212121000107
113633041006975
121310b98779177
136343b5991c31
142aa95337121d
151469bdd00e57
hexa32867d48ab

11212121000107 has 2 divisors, whose sum is σ = 11212121000108. Its totient is φ = 11212121000106.

The previous prime is 11212121000071. The next prime is 11212121000141. The reversal of 11212121000107 is 70100012121211.

Together with previous prime (11212121000071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11212121000107 - 215 = 11212120967339 is a prime.

It is a super-2 number, since 2×112121210001072 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11212121600107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606060500053 + 5606060500054.

It is an arithmetic number, because the mean of its divisors is an integer number (5606060500054).

Almost surely, 211212121000107 is an apocalyptic number.

11212121000107 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212121000107 is an equidigital number, since it uses as much as digits as its factorization.

11212121000107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 11212121000107 its reverse (70100012121211), we get a palindrome (81312133121318).

The spelling of 11212121000107 in words is "eleven trillion, two hundred twelve billion, one hundred twenty-one million, one hundred seven", and thus it is an aban number.