Base | Representation |
---|---|
bin | 1010001100101000011001… |
… | …1111010100100010101011 |
3 | 1110200212102222201222002201 |
4 | 2203022012133110202223 |
5 | 2432144410434000412 |
6 | 35502435520441031 |
7 | 2235022545012136 |
oct | 243120637244253 |
9 | 43625388658081 |
10 | 11212121000107 |
11 | 3633041006975 |
12 | 1310b98779177 |
13 | 6343b5991c31 |
14 | 2aa95337121d |
15 | 1469bdd00e57 |
hex | a32867d48ab |
11212121000107 has 2 divisors, whose sum is σ = 11212121000108. Its totient is φ = 11212121000106.
The previous prime is 11212121000071. The next prime is 11212121000141. The reversal of 11212121000107 is 70100012121211.
Together with previous prime (11212121000071) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212121000107 - 215 = 11212120967339 is a prime.
It is a super-2 number, since 2×112121210001072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11212121600107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606060500053 + 5606060500054.
It is an arithmetic number, because the mean of its divisors is an integer number (5606060500054).
Almost surely, 211212121000107 is an apocalyptic number.
11212121000107 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212121000107 is an equidigital number, since it uses as much as digits as its factorization.
11212121000107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 11212121000107 its reverse (70100012121211), we get a palindrome (81312133121318).
The spelling of 11212121000107 in words is "eleven trillion, two hundred twelve billion, one hundred twenty-one million, one hundred seven", and thus it is an aban number.
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