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112121211113 is a prime number
BaseRepresentation
bin110100001101011110…
…0011110100011101001
3101201101220211122222122
41220122330132203221
53314111012223423
6123301402401025
711046316366262
oct1503274364351
9351356748878
10112121211113
114360655644a
1219891200175
13a75ab03502
1455d8bd1969
152db344e8c8
hex1a1af1e8e9

112121211113 has 2 divisors, whose sum is σ = 112121211114. Its totient is φ = 112121211112.

The previous prime is 112121210959. The next prime is 112121211151. The reversal of 112121211113 is 311112121211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98978193664 + 13143017449 = 314608^2 + 114643^2 .

It is a cyclic number.

It is not a de Polignac number, because 112121211113 - 226 = 112054102249 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 112121211091 and 112121211100.

It is not a weakly prime, because it can be changed into another prime (112121211173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060605556 + 56060605557.

It is an arithmetic number, because the mean of its divisors is an integer number (56060605557).

Almost surely, 2112121211113 is an apocalyptic number.

It is an amenable number.

112121211113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112121211113 is an equidigital number, since it uses as much as digits as its factorization.

112121211113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24, while the sum is 17.

Adding to 112121211113 its reverse (311112121211), we get a palindrome (423233332324).

The spelling of 112121211113 in words is "one hundred twelve billion, one hundred twenty-one million, two hundred eleven thousand, one hundred thirteen".