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112122021013 is a prime number
BaseRepresentation
bin110100001101011111…
…1100100010010010101
3101201101222100210221221
41220122333210102111
53314111214133023
6123301432010341
711046326311432
oct1503277442225
9351358323857
10112122021013
1143606a59992
12198915309b1
13a75b028042
1455d8d62b89
152db355e85d
hex1a1afe4495

112122021013 has 2 divisors, whose sum is σ = 112122021014. Its totient is φ = 112122021012.

The previous prime is 112122021007. The next prime is 112122021047. The reversal of 112122021013 is 310120221211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111330330244 + 791690769 = 333662^2 + 28137^2 .

It is an emirp because it is prime and its reverse (310120221211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112122021013 - 217 = 112121889941 is a prime.

It is a super-2 number, since 2×1121220210132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112122021073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56061010506 + 56061010507.

It is an arithmetic number, because the mean of its divisors is an integer number (56061010507).

Almost surely, 2112122021013 is an apocalyptic number.

It is an amenable number.

112122021013 is a deficient number, since it is larger than the sum of its proper divisors (1).

112122021013 is an equidigital number, since it uses as much as digits as its factorization.

112122021013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 112122021013 its reverse (310120221211), we get a palindrome (422242242224).

The spelling of 112122021013 in words is "one hundred twelve billion, one hundred twenty-two million, twenty-one thousand, thirteen".