Base | Representation |
---|---|
bin | 11001011111100101110001… |
… | …010011001000010010000111 |
3 | 112200222202112111111200020212 |
4 | 121133211301103020102013 |
5 | 104144001400124232101 |
6 | 1034244051301550035 |
7 | 32421356142004565 |
oct | 3137456123102207 |
9 | 480882474450225 |
10 | 112122022102151 |
11 | 327a87565093a6 |
12 | 106a9bba41531b |
13 | 4a740a4935429 |
14 | 1d98a40506a35 |
15 | ce683ee721bb |
hex | 65f9714c8487 |
112122022102151 has 2 divisors, whose sum is σ = 112122022102152. Its totient is φ = 112122022102150.
The previous prime is 112122022102067. The next prime is 112122022102159. The reversal of 112122022102151 is 151201220221211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112122022102151 - 246 = 41753277924487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112122022102159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56061011051075 + 56061011051076.
It is an arithmetic number, because the mean of its divisors is an integer number (56061011051076).
Almost surely, 2112122022102151 is an apocalyptic number.
112122022102151 is a deficient number, since it is larger than the sum of its proper divisors (1).
112122022102151 is an equidigital number, since it uses as much as digits as its factorization.
112122022102151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 320, while the sum is 23.
Adding to 112122022102151 its reverse (151201220221211), we get a palindrome (263323242323362).
The spelling of 112122022102151 in words is "one hundred twelve trillion, one hundred twenty-two billion, twenty-two million, one hundred two thousand, one hundred fifty-one".
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