11212210002013 has 2 divisors, whose sum is σ = 11212210002014. Its totient is φ = 11212210002012.

The previous prime is 11212210001981. The next prime is 11212210002041. The reversal of 11212210002013 is 31020001221211.

11212210002013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10717884297124 + 494325704889 = 3273818^2 + 703083^2 .

It is a cyclic number.

It is not a de Polignac number, because 11212210002013 - 2⁵ = 11212210001981 is a prime.

It is a super-3 number, since 3×11212210002013³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11212210062013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606105001006 + 5606105001007.

It is an arithmetic number, because the mean of its divisors is an integer number (5606105001007).

Almost surely, 2^{11212210002013} is an apocalyptic number.

It is an amenable number.

11212210002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212210002013 is an equidigital number, since it uses as much as digits as its factorization.

11212210002013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11212210002013 its reverse (31020001221211), we get a palindrome (42232211223224).

The spelling of 11212210002013 in words is "eleven trillion, two hundred twelve billion, two hundred ten million, two thousand, thirteen".