Base | Representation |
---|---|
bin | 10100111000100110… |
… | …01100000000000111 |
3 | 1001221101202021212211 |
4 | 22130103030000013 |
5 | 140430311211213 |
6 | 5052324324251 |
7 | 544564133266 |
oct | 123423140007 |
9 | 31841667784 |
10 | 11212210183 |
11 | 4834000509 |
12 | 220ab43687 |
13 | 1098b984c5 |
14 | 7851505dd |
15 | 45950b53d |
hex | 29c4cc007 |
11212210183 has 2 divisors, whose sum is σ = 11212210184. Its totient is φ = 11212210182.
The previous prime is 11212210157. The next prime is 11212210201. The reversal of 11212210183 is 38101221211.
It is a strong prime.
It is an emirp because it is prime and its reverse (38101221211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11212210183 - 25 = 11212210151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212210133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606105091 + 5606105092.
It is an arithmetic number, because the mean of its divisors is an integer number (5606105092).
Almost surely, 211212210183 is an apocalyptic number.
11212210183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212210183 is an equidigital number, since it uses as much as digits as its factorization.
11212210183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 11212210183 its reverse (38101221211), we get a palindrome (49313431394).
The spelling of 11212210183 in words is "eleven billion, two hundred twelve million, two hundred ten thousand, one hundred eighty-three".
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