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11212211020022 = 25606105510011
BaseRepresentation
bin1010001100101000101111…
…0110101110000011110110
31110200212200021010110012122
42203022023312232003312
52432200102010120042
635502452454115542
72235025020116645
oct243121366560366
943625607113178
1011212211020022
1136330879011a1
12131100294bbb2
136343cb51cc5c
142aa9612c535c
151469c6b837d2
hexa328bdae0f6

11212211020022 has 4 divisors (see below), whose sum is σ = 16818316530036. Its totient is φ = 5606105510010.

The previous prime is 11212211020007. The next prime is 11212211020033. The reversal of 11212211020022 is 22002011221211.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×112122110200223 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2803052755004 + ... + 2803052755007.

It is an arithmetic number, because the mean of its divisors is an integer number (4204579132509).

Almost surely, 211212211020022 is an apocalyptic number.

11212211020022 is a deficient number, since it is larger than the sum of its proper divisors (5606105510014).

11212211020022 is an equidigital number, since it uses as much as digits as its factorization.

11212211020022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5606105510013.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 11212211020022 its reverse (22002011221211), we get a palindrome (33214222241233).

The spelling of 11212211020022 in words is "eleven trillion, two hundred twelve billion, two hundred eleven million, twenty thousand, twenty-two".

Divisors: 1 2 5606105510011 11212211020022