Base | Representation |
---|---|
bin | 1010001100101000101111… |
… | …0110101110000011110110 |
3 | 1110200212200021010110012122 |
4 | 2203022023312232003312 |
5 | 2432200102010120042 |
6 | 35502452454115542 |
7 | 2235025020116645 |
oct | 243121366560366 |
9 | 43625607113178 |
10 | 11212211020022 |
11 | 36330879011a1 |
12 | 131100294bbb2 |
13 | 6343cb51cc5c |
14 | 2aa9612c535c |
15 | 1469c6b837d2 |
hex | a328bdae0f6 |
11212211020022 has 4 divisors (see below), whose sum is σ = 16818316530036. Its totient is φ = 5606105510010.
The previous prime is 11212211020007. The next prime is 11212211020033. The reversal of 11212211020022 is 22002011221211.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×112122110200223 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2803052755004 + ... + 2803052755007.
It is an arithmetic number, because the mean of its divisors is an integer number (4204579132509).
Almost surely, 211212211020022 is an apocalyptic number.
11212211020022 is a deficient number, since it is larger than the sum of its proper divisors (5606105510014).
11212211020022 is an equidigital number, since it uses as much as digits as its factorization.
11212211020022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5606105510013.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11212211020022 its reverse (22002011221211), we get a palindrome (33214222241233).
The spelling of 11212211020022 in words is "eleven trillion, two hundred twelve billion, two hundred eleven million, twenty thousand, twenty-two".
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