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11212212013 is a prime number
BaseRepresentation
bin10100111000100110…
…01100011100101101
31001221101202101101121
422130103030130231
5140430311241023
65052324340541
7544564141522
oct123423143455
931841671347
1011212212013
114834001922
12220ab44751
131098b992a2
14785151149
1545950bd5d
hex29c4cc72d

11212212013 has 2 divisors, whose sum is σ = 11212212014. Its totient is φ = 11212212012.

The previous prime is 11212211993. The next prime is 11212212023. The reversal of 11212212013 is 31021221211.

11212212013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8317987209 + 2894224804 = 91203^2 + 53798^2 .

It is an emirp because it is prime and its reverse (31021221211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11212212013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11212212023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606106006 + 5606106007.

It is an arithmetic number, because the mean of its divisors is an integer number (5606106007).

Almost surely, 211212212013 is an apocalyptic number.

It is an amenable number.

11212212013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212212013 is an equidigital number, since it uses as much as digits as its factorization.

11212212013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11212212013 its reverse (31021221211), we get a palindrome (42233433224).

The spelling of 11212212013 in words is "eleven billion, two hundred twelve million, two hundred twelve thousand, thirteen".