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112122220122197 is a prime number
BaseRepresentation
bin11001011111100101111101…
…000110100001000001010101
3112200222210001022010010200122
4121133211331012201001111
5104144002301322402242
61034244123054121325
732421364065104525
oct3137457506410125
9480883038103618
10112122220122197
11327a884826982a
12106aa0547b0245
134a7410697845c
141d98a5c931685
15ce6852539ad2
hex65f97d1a1055

112122220122197 has 2 divisors, whose sum is σ = 112122220122198. Its totient is φ = 112122220122196.

The previous prime is 112122220122091. The next prime is 112122220122257. The reversal of 112122220122197 is 791221022221211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111531890669956 + 590329452241 = 10560866^2 + 768329^2 .

It is a cyclic number.

It is not a de Polignac number, because 112122220122197 - 28 = 112122220121941 is a prime.

It is a super-2 number, since 2×1121222201221972 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112122220122697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56061110061098 + 56061110061099.

It is an arithmetic number, because the mean of its divisors is an integer number (56061110061099).

Almost surely, 2112122220122197 is an apocalyptic number.

It is an amenable number.

112122220122197 is a deficient number, since it is larger than the sum of its proper divisors (1).

112122220122197 is an equidigital number, since it uses as much as digits as its factorization.

112122220122197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 35.

The spelling of 112122220122197 in words is "one hundred twelve trillion, one hundred twenty-two billion, two hundred twenty million, one hundred twenty-two thousand, one hundred ninety-seven".