11212330002017 has 2 divisors, whose sum is σ = 11212330002018. Its totient is φ = 11212330002016.

The previous prime is 11212330001959. The next prime is 11212330002019. The reversal of 11212330002017 is 71020003321211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7774750728976 + 3437579273041 = 2788324^2 + 1854071^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11212330002017 is a prime.

Together with 11212330002019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11212330001983 and 11212330002001.

It is not a weakly prime, because it can be changed into another prime (11212330002019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606165001008 + 5606165001009.

It is an arithmetic number, because the mean of its divisors is an integer number (5606165001009).

Almost surely, 2^{11212330002017} is an apocalyptic number.

It is an amenable number.

11212330002017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212330002017 is an equidigital number, since it uses as much as digits as its factorization.

11212330002017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 11212330002017 its reverse (71020003321211), we get a palindrome (82232333323228).

The spelling of 11212330002017 in words is "eleven trillion, two hundred twelve billion, three hundred thirty million, two thousand, seventeen".