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112130013143 is a prime number
BaseRepresentation
bin110100001101101111…
…0000011011111010111
3101201102112101212002202
41220123132003133113
53314120240410033
6123302315155115
711046454246211
oct1503336033727
9351375355082
10112130013143
1143610518555
1219894145a9b
13a75c895a05
1455da0435b1
152db40dc8e8
hex1a1b7837d7

112130013143 has 2 divisors, whose sum is σ = 112130013144. Its totient is φ = 112130013142.

The previous prime is 112130013109. The next prime is 112130013181. The reversal of 112130013143 is 341310031211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 112130013143 - 210 = 112130012119 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112130043143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065006571 + 56065006572.

It is an arithmetic number, because the mean of its divisors is an integer number (56065006572).

Almost surely, 2112130013143 is an apocalyptic number.

112130013143 is a deficient number, since it is larger than the sum of its proper divisors (1).

112130013143 is an equidigital number, since it uses as much as digits as its factorization.

112130013143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 112130013143 its reverse (341310031211), we get a palindrome (453440044354).

The spelling of 112130013143 in words is "one hundred twelve billion, one hundred thirty million, thirteen thousand, one hundred forty-three".