Base | Representation |
---|---|
bin | 10100111000101100… |
… | …01111010000111101 |
3 | 1001221110020220222222 |
4 | 22130112033100331 |
5 | 140431012304411 |
6 | 5052353415125 |
7 | 544604004125 |
oct | 123426172075 |
9 | 31843226888 |
10 | 11213009981 |
11 | 48344a73a8 |
12 | 220b26a4a5 |
13 | 10990b8564 |
14 | 7852bbc85 |
15 | 4596184db |
hex | 29c58f43d |
11213009981 has 2 divisors, whose sum is σ = 11213009982. Its totient is φ = 11213009980.
The previous prime is 11213009909. The next prime is 11213010013. The reversal of 11213009981 is 18990031211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7419065956 + 3793944025 = 86134^2 + 61595^2 .
It is a cyclic number.
It is not a de Polignac number, because 11213009981 - 210 = 11213008957 is a prime.
It is a super-2 number, since 2×112130099812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11213009281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606504990 + 5606504991.
It is an arithmetic number, because the mean of its divisors is an integer number (5606504991).
Almost surely, 211213009981 is an apocalyptic number.
It is an amenable number.
11213009981 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213009981 is an equidigital number, since it uses as much as digits as its factorization.
11213009981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 35.
The spelling of 11213009981 in words is "eleven billion, two hundred thirteen million, nine thousand, nine hundred eighty-one".
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