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11213041633 is a prime number
BaseRepresentation
bin10100111000101100…
…10110111111100001
31001221110022112102021
422130112112333201
5140431014313013
65052354221441
7544604165323
oct123426267741
931843275367
1011213041633
114834519162
12220b284881
1310990c9aa1
147852c9613
15459622a8d
hex29c596fe1

11213041633 has 2 divisors, whose sum is σ = 11213041634. Its totient is φ = 11213041632.

The previous prime is 11213041613. The next prime is 11213041687. The reversal of 11213041633 is 33614031211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9520295184 + 1692746449 = 97572^2 + 41143^2 .

It is an emirp because it is prime and its reverse (33614031211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11213041633 - 25 = 11213041601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11213041598 and 11213041607.

It is not a weakly prime, because it can be changed into another prime (11213041613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606520816 + 5606520817.

It is an arithmetic number, because the mean of its divisors is an integer number (5606520817).

Almost surely, 211213041633 is an apocalyptic number.

It is an amenable number.

11213041633 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213041633 is an equidigital number, since it uses as much as digits as its factorization.

11213041633 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 11213041633 its reverse (33614031211), we get a palindrome (44827072844).

The spelling of 11213041633 in words is "eleven billion, two hundred thirteen million, forty-one thousand, six hundred thirty-three".