Base | Representation |
---|---|
bin | 1010001100101100000101… |
… | …1101010100101101100001 |
3 | 1110200221222221100020200012 |
4 | 2203023001131110231201 |
5 | 2432203422221113012 |
6 | 35503122021334305 |
7 | 2235056220132341 |
oct | 243130135245541 |
9 | 43627887306605 |
10 | 11213110332257 |
11 | 36334a9503849 |
12 | 1311213b67395 |
13 | 634512935582 |
14 | 2aaa08902d21 |
15 | 146a2aac6622 |
hex | a32c1754b61 |
11213110332257 has 2 divisors, whose sum is σ = 11213110332258. Its totient is φ = 11213110332256.
The previous prime is 11213110332241. The next prime is 11213110332313. The reversal of 11213110332257 is 75223301131211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10099232729041 + 1113877603216 = 3177929^2 + 1055404^2 .
It is a cyclic number.
It is not a de Polignac number, because 11213110332257 - 24 = 11213110332241 is a prime.
It is not a weakly prime, because it can be changed into another prime (11213110332857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606555166128 + 5606555166129.
It is an arithmetic number, because the mean of its divisors is an integer number (5606555166129).
Almost surely, 211213110332257 is an apocalyptic number.
It is an amenable number.
11213110332257 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213110332257 is an equidigital number, since it uses as much as digits as its factorization.
11213110332257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 32.
Adding to 11213110332257 its reverse (75223301131211), we get a palindrome (86436411463468).
The spelling of 11213110332257 in words is "eleven trillion, two hundred thirteen billion, one hundred ten million, three hundred thirty-two thousand, two hundred fifty-seven".
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