11213120213 has 2 divisors, whose sum is σ = 11213120214. Its totient is φ = 11213120212.

The previous prime is 11213120203. The next prime is 11213120231. The reversal of 11213120213 is 31202131211.

11213120213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (11213120231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10849722244 + 363397969 = 104162^2 + 19063^2 .

It is a cyclic number.

It is not a de Polignac number, because 11213120213 - 2¹⁰ = 11213119189 is a prime.

It is a super-2 number, since 2×11213120213² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11213120191 and 11213120200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11213120203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606560106 + 5606560107.

It is an arithmetic number, because the mean of its divisors is an integer number (5606560107).

Almost surely, 2^11213120213 is an apocalyptic number.

It is an amenable number.

11213120213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213120213 is an equidigital number, since it uses as much as digits as its factorization.

11213120213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11213120213 its reverse (31202131211), we get a palindrome (42415251424).

The spelling of 11213120213 in words is "eleven billion, two hundred thirteen million, one hundred twenty thousand, two hundred thirteen".