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1121312201117 is a prime number
BaseRepresentation
bin10000010100010011011…
…010100101100110011101
310222012022011201202111212
4100110103122211212131
5121332421410413432
62215042415554205
7144004106306453
oct20242332454635
93865264652455
101121312201117
113a2600561149
1216139922b965
138197c2a0574
143c3b3b689d3
151e27ba1c2b2
hex105136a599d

1121312201117 has 2 divisors, whose sum is σ = 1121312201118. Its totient is φ = 1121312201116.

The previous prime is 1121312201089. The next prime is 1121312201147. The reversal of 1121312201117 is 7111022131211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1088556268921 + 32755932196 = 1043339^2 + 180986^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121312201117 - 224 = 1121295423901 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1121312201092 and 1121312201101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121312201147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560656100558 + 560656100559.

It is an arithmetic number, because the mean of its divisors is an integer number (560656100559).

Almost surely, 21121312201117 is an apocalyptic number.

It is an amenable number.

1121312201117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121312201117 is an equidigital number, since it uses as much as digits as its factorization.

1121312201117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 23.

Adding to 1121312201117 its reverse (7111022131211), we get a palindrome (8232334332328).

The spelling of 1121312201117 in words is "one trillion, one hundred twenty-one billion, three hundred twelve million, two hundred one thousand, one hundred seventeen".