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1121313344453 is a prime number
BaseRepresentation
bin10000010100010011011…
…110111100101111000101
310222012022020212211212122
4100110103132330233011
5121332422204010303
62215042500255325
7144004122111011
oct20242336745705
93865266784778
101121313344453
113a2601172155
121613996a1545
138197c5b0ab3
143c3b3d85541
151e27bb95e38
hex105137bcbc5

1121313344453 has 2 divisors, whose sum is σ = 1121313344454. Its totient is φ = 1121313344452.

The previous prime is 1121313344443. The next prime is 1121313344509. The reversal of 1121313344453 is 3544433131211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 812374137124 + 308939207329 = 901318^2 + 555823^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1121313344453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121313344413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560656672226 + 560656672227.

It is an arithmetic number, because the mean of its divisors is an integer number (560656672227).

Almost surely, 21121313344453 is an apocalyptic number.

It is an amenable number.

1121313344453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121313344453 is an equidigital number, since it uses as much as digits as its factorization.

1121313344453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 51840, while the sum is 35.

Adding to 1121313344453 its reverse (3544433131211), we get a palindrome (4665746475664).

The spelling of 1121313344453 in words is "one trillion, one hundred twenty-one billion, three hundred thirteen million, three hundred forty-four thousand, four hundred fifty-three".