Base | Representation |
---|---|
bin | 10000010100010011111… |
… | …100001001110010110001 |
3 | 10222012022210021210110121 |
4 | 100110103330021302301 |
5 | 121332431134000423 |
6 | 2215043332330241 |
7 | 144004244144506 |
oct | 20242374116261 |
9 | 3865283253417 |
10 | 1121321000113 |
11 | 3a2605520a46 |
12 | 1613a0173981 |
13 | 81981061582 |
14 | 3c3b4db94ad |
15 | 1e27c6a945d |
hex | 10513f09cb1 |
1121321000113 has 2 divisors, whose sum is σ = 1121321000114. Its totient is φ = 1121321000112.
The previous prime is 1121321000101. The next prime is 1121321000143. The reversal of 1121321000113 is 3110001231211.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 744187451569 + 377133548544 = 862663^2 + 614112^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121321000113 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121321000143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560660500056 + 560660500057.
It is an arithmetic number, because the mean of its divisors is an integer number (560660500057).
Almost surely, 21121321000113 is an apocalyptic number.
It is an amenable number.
1121321000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121321000113 is an equidigital number, since it uses as much as digits as its factorization.
1121321000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 1121321000113 its reverse (3110001231211), we get a palindrome (4231322231324).
The spelling of 1121321000113 in words is "one trillion, one hundred twenty-one billion, three hundred twenty-one million, one hundred thirteen", and thus it is an aban number.
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