Base | Representation |
---|---|
bin | 10100111000101110… |
… | …11000100000111101 |
3 | 1001221110211011120021 |
4 | 22130113120200331 |
5 | 140431101410023 |
6 | 5052404052141 |
7 | 544606363633 |
oct | 123427304075 |
9 | 31843734507 |
10 | 11213310013 |
11 | 4834691864 |
12 | 220b394051 |
13 | 1099191ca9 |
14 | 785359353 |
15 | 45967735d |
hex | 29c5d883d |
11213310013 has 2 divisors, whose sum is σ = 11213310014. Its totient is φ = 11213310012.
The previous prime is 11213309999. The next prime is 11213310071. The reversal of 11213310013 is 31001331211.
11213310013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10925057529 + 288252484 = 104523^2 + 16978^2 .
It is a cyclic number.
It is not a de Polignac number, because 11213310013 - 29 = 11213309501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11213310113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606655006 + 5606655007.
It is an arithmetic number, because the mean of its divisors is an integer number (5606655007).
Almost surely, 211213310013 is an apocalyptic number.
It is an amenable number.
11213310013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213310013 is an equidigital number, since it uses as much as digits as its factorization.
11213310013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11213310013 its reverse (31001331211), we get a palindrome (42214641224).
The spelling of 11213310013 in words is "eleven billion, two hundred thirteen million, three hundred ten thousand, thirteen".
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