Base | Representation |
---|---|
bin | 10000010100010100100… |
… | …010101110110010001101 |
3 | 10222012100111022120212201 |
4 | 100110110202232302031 |
5 | 121332441231104401 |
6 | 2215044333201501 |
7 | 144004426124443 |
oct | 20242442566215 |
9 | 3865314276781 |
10 | 1121331113101 |
11 | 3a26101a8a91 |
12 | 1613a3630291 |
13 | 819831926a4 |
14 | 3c3b648cb93 |
15 | 1e27d505b01 |
hex | 105148aec8d |
1121331113101 has 2 divisors, whose sum is σ = 1121331113102. Its totient is φ = 1121331113100.
The previous prime is 1121331113041. The next prime is 1121331113107. The reversal of 1121331113101 is 1013111331211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 940919400100 + 180411713001 = 970010^2 + 424749^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121331113101 - 29 = 1121331112589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121331113107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560665556550 + 560665556551.
It is an arithmetic number, because the mean of its divisors is an integer number (560665556551).
Almost surely, 21121331113101 is an apocalyptic number.
It is an amenable number.
1121331113101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121331113101 is an equidigital number, since it uses as much as digits as its factorization.
1121331113101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 1121331113101 its reverse (1013111331211), we get a palindrome (2134442444312).
The spelling of 1121331113101 in words is "one trillion, one hundred twenty-one billion, three hundred thirty-one million, one hundred thirteen thousand, one hundred one".
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