Base | Representation |
---|---|
bin | 10100111000101110… |
… | …11011000000011011 |
3 | 1001221110211200120021 |
4 | 22130113123000123 |
5 | 140431102221334 |
6 | 5052404211311 |
7 | 544606435453 |
oct | 123427330033 |
9 | 31843750507 |
10 | 11213320219 |
11 | 48346994a2 |
12 | 220b399b37 |
13 | 109919682a |
14 | 78535cd63 |
15 | 45967a3b4 |
hex | 29c5db01b |
11213320219 has 2 divisors, whose sum is σ = 11213320220. Its totient is φ = 11213320218.
The previous prime is 11213320189. The next prime is 11213320243. The reversal of 11213320219 is 91202331211.
11213320219 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11213320219 - 27 = 11213320091 is a prime.
It is a super-2 number, since 2×112133202192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11213320193 and 11213320202.
It is not a weakly prime, because it can be changed into another prime (11213320259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606660109 + 5606660110.
It is an arithmetic number, because the mean of its divisors is an integer number (5606660110).
Almost surely, 211213320219 is an apocalyptic number.
11213320219 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213320219 is an equidigital number, since it uses as much as digits as its factorization.
11213320219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 11213320219 in words is "eleven billion, two hundred thirteen million, three hundred twenty thousand, two hundred nineteen".
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