Base | Representation |
---|---|
bin | 11001011111110000010010… |
… | …000111111010111001100001 |
3 | 112201000211200012002222202021 |
4 | 121133300102013322321201 |
5 | 104144143004404330423 |
6 | 1034253155341421441 |
7 | 32422235650342624 |
oct | 3137602207727141 |
9 | 481024605088667 |
10 | 112133310230113 |
11 | 32802519351a77 |
12 | 106b022a86a881 |
13 | 4a75183461ba3 |
14 | 1d993d1779dbb |
15 | ce6ca0e7795d |
hex | 65fc121fae61 |
112133310230113 has 8 divisors (see below), whose sum is σ = 114520269128832. Its totient is φ = 109746398989296.
The previous prime is 112133310230099. The next prime is 112133310230129. The reversal of 112133310230113 is 311032013331211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 112133310230113 - 213 = 112133310221921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (112133310230153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7138470 + ... + 16589887.
It is an arithmetic number, because the mean of its divisors is an integer number (14315033641104).
Almost surely, 2112133310230113 is an apocalyptic number.
It is an amenable number.
112133310230113 is a deficient number, since it is larger than the sum of its proper divisors (2386958898719).
112133310230113 is a wasteful number, since it uses less digits than its factorization.
112133310230113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23828951.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 112133310230113 its reverse (311032013331211), we get a palindrome (423165323561324).
The spelling of 112133310230113 in words is "one hundred twelve trillion, one hundred thirty-three billion, three hundred ten million, two hundred thirty thousand, one hundred thirteen".
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