Base | Representation |
---|---|
bin | 11001011111110000010011… |
… | …000001101010000100110101 |
3 | 112201000211201020120221200021 |
4 | 121133300103001222010311 |
5 | 104144143022243144212 |
6 | 1034253201042045141 |
7 | 32422236223111366 |
oct | 3137602301520465 |
9 | 481024636527607 |
10 | 112133325365557 |
11 | 3280252694a501 |
12 | 106b02339497b1 |
13 | 4a75186631082 |
14 | 1d993d3799b6d |
15 | ce6ca2467307 |
hex | 65fc1306a135 |
112133325365557 has 2 divisors, whose sum is σ = 112133325365558. Its totient is φ = 112133325365556.
The previous prime is 112133325365483. The next prime is 112133325365599. The reversal of 112133325365557 is 755563523331211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110701667648196 + 1431657717361 = 10521486^2 + 1196519^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112133325365557 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112133325375557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56066662682778 + 56066662682779.
It is an arithmetic number, because the mean of its divisors is an integer number (56066662682779).
Almost surely, 2112133325365557 is an apocalyptic number.
It is an amenable number.
112133325365557 is a deficient number, since it is larger than the sum of its proper divisors (1).
112133325365557 is an equidigital number, since it uses as much as digits as its factorization.
112133325365557 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8505000, while the sum is 52.
Adding to 112133325365557 its reverse (755563523331211), we get a palindrome (867696848696768).
The spelling of 112133325365557 in words is "one hundred twelve trillion, one hundred thirty-three billion, three hundred twenty-five million, three hundred sixty-five thousand, five hundred fifty-seven".
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