Base | Representation |
---|---|
bin | 1010001100101100111011… |
… | …0000000000010110000111 |
3 | 1110200222120110221212201011 |
4 | 2203023032300000112013 |
5 | 2432204401313132013 |
6 | 35503200105143051 |
7 | 2235064565455366 |
oct | 243131660002607 |
9 | 43628513855634 |
10 | 11213333333383 |
11 | 36336033768a5 |
12 | 131127678aa87 |
13 | 634549bb3cbc |
14 | 2aaa2a3917dd |
15 | 146a40475c3d |
hex | a32cec00587 |
11213333333383 has 2 divisors, whose sum is σ = 11213333333384. Its totient is φ = 11213333333382.
The previous prime is 11213333333359. The next prime is 11213333333399. The reversal of 11213333333383 is 38333333331211.
It is a strong prime.
It is an emirp because it is prime and its reverse (38333333331211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11213333333383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11213333303383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606666666691 + 5606666666692.
It is an arithmetic number, because the mean of its divisors is an integer number (5606666666692).
Almost surely, 211213333333383 is an apocalyptic number.
11213333333383 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213333333383 is an equidigital number, since it uses as much as digits as its factorization.
11213333333383 is an evil number, because the sum of its binary digits is even.
The product of its digits is 314928, while the sum is 40.
Adding to 11213333333383 its reverse (38333333331211), we get a palindrome (49546666664594).
The spelling of 11213333333383 in words is "eleven trillion, two hundred thirteen billion, three hundred thirty-three million, three hundred thirty-three thousand, three hundred eighty-three".
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