Base | Representation |
---|---|
bin | 1010001100101101001010… |
… | …1111001010001100100111 |
3 | 1110200222202010211002112010 |
4 | 2203023102233022030213 |
5 | 2432210020424023310 |
6 | 35503210454525303 |
7 | 2235066340135416 |
oct | 243132257121447 |
9 | 43628663732463 |
10 | 11213400220455 |
11 | 3633638101074 |
12 | 1311295066833 |
13 | 63455aa02954 |
14 | 2aaa3520347d |
15 | 146a46289320 |
hex | a32d2bca327 |
11213400220455 has 32 divisors (see below), whose sum is σ = 17979522107904. Its totient is φ = 5967787902336.
The previous prime is 11213400220433. The next prime is 11213400220469. The reversal of 11213400220455 is 55402200431211.
11213400220455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11213400220455 - 220 = 11213399171879 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 126456364 + ... + 126545006.
It is an arithmetic number, because the mean of its divisors is an integer number (561860065872).
Almost surely, 211213400220455 is an apocalyptic number.
11213400220455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11213400220455 is a deficient number, since it is larger than the sum of its proper divisors (6766121887449).
11213400220455 is a wasteful number, since it uses less digits than its factorization.
11213400220455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106455.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 11213400220455 its reverse (55402200431211), we get a palindrome (66615600651666).
The spelling of 11213400220455 in words is "eleven trillion, two hundred thirteen billion, four hundred million, two hundred twenty thousand, four hundred fifty-five".
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