112134404131 has 2 divisors, whose sum is σ = 112134404132. Its totient is φ = 112134404130.

The previous prime is 112134404087. The next prime is 112134404177. The reversal of 112134404131 is 131404431211.

It is a weak prime.

It is an emirp because it is prime and its reverse (131404431211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112134404131 - 2¹³ = 112134395939 is a prime.

It is a super-2 number, since 2×112134404131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112134404096 and 112134404105.

It is not a weakly prime, because it can be changed into another prime (112144404131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56067202065 + 56067202066.

It is an arithmetic number, because the mean of its divisors is an integer number (56067202066).

Almost surely, 2^112134404131 is an apocalyptic number.

112134404131 is a deficient number, since it is larger than the sum of its proper divisors (1).

112134404131 is an equidigital number, since it uses as much as digits as its factorization.

112134404131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 112134404131 its reverse (131404431211), we get a palindrome (243538835342).

The spelling of 112134404131 in words is "one hundred twelve billion, one hundred thirty-four million, four hundred four thousand, one hundred thirty-one".