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112139810611553 is a prime number
BaseRepresentation
bin11001011111110110010101…
…100100111010000101100001
3112201001110110012201120201102
4121133312111210322011201
5104144244313004032203
61034300152351244145
732422556021564204
oct3137662544720541
9481043405646642
10112139810611553
113280525467a83a
12106b1543819655
134a7597b0b753a
141d9984abdd93b
15ce70319a1888
hex65fd9593a161

112139810611553 has 2 divisors, whose sum is σ = 112139810611554. Its totient is φ = 112139810611552.

The previous prime is 112139810611487. The next prime is 112139810611567. The reversal of 112139810611553 is 355116018931211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66004851689569 + 46134958921984 = 8124337^2 + 6792272^2 .

It is a cyclic number.

It is not a de Polignac number, because 112139810611553 - 230 = 112138736869729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112139810611498 and 112139810611507.

It is not a weakly prime, because it can be changed into another prime (112139810611573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56069905305776 + 56069905305777.

It is an arithmetic number, because the mean of its divisors is an integer number (56069905305777).

Almost surely, 2112139810611553 is an apocalyptic number.

It is an amenable number.

112139810611553 is a deficient number, since it is larger than the sum of its proper divisors (1).

112139810611553 is an equidigital number, since it uses as much as digits as its factorization.

112139810611553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 47.

The spelling of 112139810611553 in words is "one hundred twelve trillion, one hundred thirty-nine billion, eight hundred ten million, six hundred eleven thousand, five hundred fifty-three".