Base | Representation |
---|---|
bin | 1010001100110011101010… |
… | …1001010101101010001111 |
3 | 1110201011020122011010210101 |
4 | 2203030322221111222033 |
5 | 2432222103220300012 |
6 | 35504055451551531 |
7 | 2235160466031112 |
oct | 243147251255217 |
9 | 43634218133711 |
10 | 11215143525007 |
11 | 3634352161634 |
12 | 13116a0a5b5a7 |
13 | 634777c31bc6 |
14 | 2aab5c95c579 |
15 | 146ae9343d57 |
hex | a333aa55a8f |
11215143525007 has 2 divisors, whose sum is σ = 11215143525008. Its totient is φ = 11215143525006.
The previous prime is 11215143524993. The next prime is 11215143525023. The reversal of 11215143525007 is 70052534151211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11215143525007 - 223 = 11215135136399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11215143525067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607571762503 + 5607571762504.
It is an arithmetic number, because the mean of its divisors is an integer number (5607571762504).
Almost surely, 211215143525007 is an apocalyptic number.
11215143525007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11215143525007 is an equidigital number, since it uses as much as digits as its factorization.
11215143525007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42000, while the sum is 37.
Adding to 11215143525007 its reverse (70052534151211), we get a palindrome (81267677676218).
The spelling of 11215143525007 in words is "eleven trillion, two hundred fifteen billion, one hundred forty-three million, five hundred twenty-five thousand, seven".
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