Search a number
-
+
1121999999941 is a prime number
BaseRepresentation
bin10000010100111100011…
…010010101001111000101
310222021002002221120010101
4100110330122111033011
5121340323444444231
62215234545524101
7144030130433032
oct20247432251705
93867062846111
101121999999941
113a2923827627
1216154b643631
1381a5b92a212
143c43b248389
151e2bc0ce661
hex1053c6953c5

1121999999941 has 2 divisors, whose sum is σ = 1121999999942. Its totient is φ = 1121999999940.

The previous prime is 1121999999933. The next prime is 1122000000041. The reversal of 1121999999941 is 1499999991211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 748318422916 + 373681577025 = 865054^2 + 611295^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121999999941 - 23 = 1121999999933 is a prime.

It is a super-3 number, since 3×11219999999413 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121999939941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560999999970 + 560999999971.

It is an arithmetic number, because the mean of its divisors is an integer number (560999999971).

Almost surely, 21121999999941 is an apocalyptic number.

It is an amenable number.

1121999999941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121999999941 is an equidigital number, since it uses as much as digits as its factorization.

1121999999941 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 38263752, while the sum is 73.

The spelling of 1121999999941 in words is "one trillion, one hundred twenty-one billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred forty-one".